201005302212 无聊写写
14年前 (2010-05-30) 作者:iMoke 分类:原创·曾经往事 阅读次数:2459 评论(0)忙中偷闲,写了一个小程序,有人能破解出来吗?
忙中偷闲,写了一个小程序,有人能破解出来吗?
<script language="javascript"> function get_time() { var date=new Date(); var year="",month="",day="",week="",hour="",minute="",second=""; year=date.getYear(); month=add_zero(date.getMonth()+1); day=add_zero(date.getDate()); week=date.getDay(); switch (date.getDay()) { case 0:val="星期日"; breakcase; 1:val="星期一"; breakcase; 2:val="星期二"; breakcase; 3:val="星期三"; breakcase; 4:val="星期四"; breakcase; 5:val="星期五"; breakcase; 6:val="星期六"; breakcase; } hour=add_zero(date.getHours()); minute=add_zero(date.getMinutes()); second=add_zero(date.getSeconds()); timetable.innerText=year+"年"+month+"月"+day+"日"+" "+val+" "+hour+"时"+minute+"分"+second+"秒";} function add_zero(temp) {if(temp<10) return "0"+temp;else return temp;} setInterval("get_time()",1000); </script> <!--当前时间end--> <!--高考倒计时start--> <div id="timetable"></div> <div> <span class="style1"> <div class="Bjtim" id="times"> </div> </span> <script language="JavaScript"> var now = new Date(); function createtime() { //var grt= new Date("06/06/2010 08:00:00"); var grt= new Date("06/07/2010 08:30:00"); now.setTime(now.getTime()+1000); days = (grt - now) / 1000 / 60 / 60 / 24; dnum = Math.floor(days); hours = (grt - now) / 1000 / 60 / 60 - (24 * dnum); hnum = Math.floor(hours); if(String(hnum).length ==1 ) {hnum = "0" + hnum;} minutes = (grt - now) / 1000 /60 - (24 * 60 * dnum) - (60 * hnum); mnum = Math.floor(minutes);if(String(mnum).length ==1 ) {mnum = "0" + mnum;} seconds = (grt - now) / 1000 - (24 * 60 * 60 * dnum) - (60 * 60 * hnum) - (60 * mnum); snum = Math.round(seconds);if(String(snum).length ==1 ) {snum = "0" + snum;} document.getElementById("times").innerHTML ="距2010年高考还有" + dnum +"天"+ hnum +"时"+ mnum +"<span style='margin:0 7px 0 7px'>分</span><font color=red>"+snum+"</font>秒"} setInterval("createtime()",1000); </script> <!--高考倒计时end--> <!--分手计时器start--> <script language="javascript" type="text/javascript"> function abDay(y,m,d) { today = new Date(); apday = new Date(y,m-1,d); dayms = 24 * 60 * 60 * 1000; n = Math.floor((apday.getTime()-today.getTime())/dayms) + 1;document.write(-n);} </script>今天是分手后的第<span style="color:#ff0000"><strong><script language="JavaScript">abDay(2010,03,05);</script></strong></span>天。 <!--分手计时器end--> <br/> <span style="font-family:HAKUYOGuiFanZi3500;font-size:32px">—傲孤漠客</span> </div>
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